WebFeb 17, 2024 · The idea here is, we will try to find the number of AND values (sub-arrays with bit-wise and (&)) with ith bit set. Let us suppose, there are ‘Si‘ number of sub-arrays with ith bit set. For, ith bit, sum can be updated as …

Count distinct Bitwise OR of all subarrays - Coding Ninjas

Web• denotes Bitwise OR operator • A subarray is an array obtained by removing zero or more elements from the front and back of the original array without changing the order of the remaining elements Example Assumptions N = 3 A = [1, 2, 3] Q = 3 Queries = [1, 2, 6] Approach The array B = {1, (1 2), (1 2 3), 2, (2 3), 3} = {1, 3, 3, 2, 3, 3} WebJul 8, 2024 · A Computer Science portal for geeks. It contains well written, well thought and well explained computer science and programming articles, quizzes and practice/competitive programming/company interview Questions. read radish

Sum of Bitwise-OR of all subarrays of a given Array Set 2

WebAug 5, 2024 · The most efficient and simple way to deal with is problem is: Step 1: calculate the xor of prefixes : xorArr [0] = arr [0] #here arr = [13,8,5,3,3] for i in range (1, n): xorArr [i] = xorArr [i - 1] ^ arr [i] Step 2: Check if at any point xorArr [i]=0, if yes then arr [:i+1] is one subarray whose xor is zero: WebAnd bitwise ORs of all the elements for all the subarrays will be 1,2,3,3,3,3 respectively. So, the count of distinct OR will be 3. Sample Input 2: 1 2 1 5 Sample Output 2: 2 Explanation for sample input 2: The possible subarrays of {1,5} are {1},{5},{1,5}. And bitwise ORs of the elements for all the subarrays will be 1,5,5 respectively. WebNov 25, 2024 · Solution 1: Brute Force Intuition: The brute force solution is to generate all possible subarrays. For each generated subarray we get the respective XOR and then check if this XOR is equal to B. If it is then we increment the count. In the end, we will get the count of all possible subarrays that have XOR equal to B. Approach: read raj comics online